CnH2n + (3n/2) O2 = nCO2 + nH2O
xL (3n/2)xL nxL nxL
CnH(2n-2) + (3m-1/2) = mCO2 + (m-1)H2O
yL (3m-1/2)yL myL (m-1)yL
x+y=1------①
nx+my=3.6------------②
nx+(m-1)y=3----------③
由②③得,
x=0.4 y=0.6
∴L(烯烃)：L（炔烃）= 2：3
烯烃燃烧,前后体积相等.
0.4 + 0.6n = 0.4n + 0.4n
∴n=2 ∴烯烃为C2H4
同理,0.6 + 0.3（3m-1) = 0.6m + 0.6(m-1)
∴m=3 ∴炔烃为C3H4
好了,