已知|a|=2,|b|=1,a与b的夹角为丌/3,求向量2a+3b,与3a-b的夹角?
人气:331 ℃ 时间:2020-04-15 03:54:11
解答
|a|=2,|b|=1.a.b = |a||b|cos丌/3a.b = 1|2a+3b|^2 =(2a+3b).(2a+3b)=4|a|^2+9|b|^2+ 12a.b=16+9+12=37|3a-b|^2 = 9|a|^2+|b|^2 - 6a.b =36+1-6=31let 2a+3b,与3a-b的夹角 = x(2a+3b).(3a-b)= |2a+3b||3a-b|cosx6|a|...
推荐
猜你喜欢
- 高中英语阅读中we can know from para.1 that…这类型的题是不是推理判断题?
- give are special you something going them to )连词成句
- 被动语态的问题
- 光合作用中葡萄糖、淀粉、蔗糖的合成部位分别是?
- 把1,2,…,2009,2009个数均匀排成一个大圆圈,从1数,隔过1划掉2,…这样划下去,最后剩下的数是多少?
- 有一古诗选集五言绝句比七言绝句多十二首,总字数少了二十个字,两种诗各有几首
- he went to bed.he did not have supper last night何为一句话he went to bed()()supper last night
- __ You go to the beach?Yes,of course