[ (x+3) / (x² -9 ) + x / (x²+x-6) ] *(x+3)
= { (x+3) / [ (x+3)(x-3) ] + x / [ (x+3)(x-2) ] } *(x+3)
= (x+3)/(x-3) + x / (x-2)
= [ (x+3)(x-2) + x(x-3) ] / [ (x-3)(x-2) ]
= [ x² +x - 6 + x² - 3x ] / [ (x-3)(x-2) ]
= [ 2x² - 2x - 6 ] / [ (x-3)(x-2) ]
= 2 ( x² - x - 3 ) / (x² - 5x + 6)
请确认题目无误