当,2-x>0,即x<2
f(x)＜[(k+1)x-k]/(2-x)
x^2/(2-x)＜[(k+1)x-k]/(2-x)
x^2-（k+1)x+k<0
(x-1)(x-k)<0
①k=1,则无解
②2>=k>1,1 ③k>2,1④0当2-x<0,即x>2
x^2-（k+1)x+k>0
(x-1)(x-k)>0
①k=1,x不为1
②02
③2>=k>1,x>2
④k>2,x>k