已知函数f(x)=2cosx/2(根号3cosx/2-sinx/2)在三角形ABC中c=1f(c)=根3+1面积=根3/2求sinA+sinB f(c)=2cosc/2(√3cosc/2-sinc/2)=2√3(cosc/2)²-2(sinc/2)(cosc/2)=2√3*(cosc+1)/2-sinc=√3cosc+√3-sinc=√3-(s...