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求数列{(n+1)²+1/(n+1)²-1}的前n项和
人气:497 ℃ 时间:2020-04-15 13:01:11
解答
an =[(n+1)^2+ 1]/[(n+1)^2 -1]
= 1 + 2/[(n+1)^2 -1]
= 1+ 2/[n(n+2)]
= 1+ [1/n - 1/(n+2) ]
Sn = a1+a2+...+an
= n + [ 1+ 1/2 - 1/(n+1) -1/(n+2) ]
= n + 3/2 - 1/(n+1) -1/(n+2)
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