y'=[2^(sin(2x)+1)]'=[2^(sin(2x)+1)]*(ln2)*(sin(2x)+1)'=[2^(sin(2x)+1)]*(ln2)*(cos2x)*(2x)'=[2^(sin(2x)+1)]*(ln2)*(cos2x)*2;用的是复合函数求导公式,{f[g(x)]}'={f'[g(x)]}*[g(x)]'.注意：f'[g(x)]是先求f（x...