(x²-2x-2)/(x-1)
=[(x-1)²-3]/(x-1)
=(x-1) -3/(x-1)
∵结果是整数
∴x-1=-3 x-1=-1 x-1=1 x-1=3
∴x=-2 x=0 x=2 x=4x²-2x-2怎么能便成(x-1)²-3？不应该是(x-1)²-1么x²-2x-2=x²-2x+1-3=(x-1)²-3 (x-1)²-1=x²-2x+1-1=x²-2x