f(x)=ab=2cos²x+√3sin2x-1=2cos²x-1+√3sin2x=cos2x+√3sin2x=2[(1/2)cos2x+(√3/2)sin2x]=2(sinπ/6cos2x+cosπ/6sin2x)=2sin(2x+π/6)(1).T=2π/2=π(2)-π/2+2kπ≤2x+π/6≤π/2+2kπ-2π/3+2kπ≤2x...若将函数f（x）的图像的纵坐标保持不变，横坐标扩大到原来的的两倍，然后再向右平移π/6个单位得到g（x）的图像，求其解析式g(x)=2sin[(1/2)*2(x-π/6)+π/6]=2sinx