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化简(2sin50°+sin10°)/cos10°
人气:443 ℃ 时间:2020-08-16 22:58:49
解答
(2sin50°+sin10°)/cos10°
=[2sin(60°-10°)+sin10°]/cos10°
=[2sin60°cos10°-cos60°sin10°+sin10°]/cos10°
=[√3cos10°-sin10°+sin10°]/cos10°
=√3cos10°/cos10°
=√3
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