用分离参数解决.f(x)=x²-2mx+2m+1>0,即2m>(x²+1)/(x-1)=（x²-1+2）/(x-1)=(x-1)+[2/(x-1)]+2x∈【0,1】,故t=x-1∈[-1,0],f(t)=t+2/t+2.f(t)在【-1,0)上递减,∴2m>f(t)max=f(-1)=-1故m>-1/2...