先通分,得k/(x-2)=[k(x-2)+1]/(x-2)k/(x-2)=(kx-2k+1)/(x-2).①要使该分式方程无解,只需让x的取值使得分母为0即可,也就是x-2=0,解得：x=2.再去求在x=2的情况下k的值.观察①式,分母相同,则分子相等,得k=kx-2k+1k=k×2...