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求极限值 lim(3^n+2^2n)/(3^(n+1)+2^(2n+1))=
人气:131 ℃ 时间:2020-05-08 19:53:06
解答
lim(3^n+2^2n)/(3^(n+1)+2^(2n+1))
= lim(n-->∞)[(3^n+4^n)/(3*3^n+2*4^n)]
= lim(n-->∞)[(3/4)^n+1]/[3*(3/4)^n+2*] (分子分母同时除以4^n)
=(0+1)/(0+2)
=1/2
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