∵函数f(x)＝4xx2+1，x∈[−2，2]，∴f′(x)＝4(x2+1)−2x•4x(x2+1)2＝−4(x+1)(x−1)(x2+1)2．∴当-2≤x＜-1时，f′（x）＜0，f（x）单调递减；  当-1＜x＜1时，f′（x）＞0，f（x）单调递增； &nb...