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∫cost/(sint+cost)dt在0到π取积分
人气:385 ℃ 时间:2020-03-29 02:43:51
解答
∫ cost/(sint + cost) dt= (1/2)∫ [(cost + sint) + (cost - sint)]/(sint + cost) dt= (1/2)∫ [1 + (cost - sint)/(sint + cost)] dt= t/2 + (1/2)ln|sint + cost| + C设ƒ(t) = cost/(sint + cost) ∫(0→...
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