Z=f'x(x,y)=xy*[x^(xy-1)]*y
Z=f'y(x,y)=xy*[x^(xy-1)]*x答案是Z=f'x(x,y)=yx^xy(lnx+1),Z=f'y(x,y)=x^(xy+1)lnx,求解答过程请问是Z=（x^x）y还是Z=x^（xy）Z=x^（xy）Z=x^(xy)两边取对数：lnZ=xylnx两边同时对x取导有Zx/Z=ylnx+xy/x=ylnx+y有：Zx=x^(xy)[ylnx+y]=yx^xy(lnx+1),两边同时对y取导有：Zy/Z=xlnx则有：Zy=xlnx[x^(xy)]=x^(xy+1)lnxZx=x^(xy)[ylnx+y]，为什么要乘起来？