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数学
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已知tan^2a=2tan^2b+1,求证:sin^b=2sin^2a-1
人气:307 ℃ 时间:2020-03-23 22:36:06
解答
tan^2a=2tan^2b+1sin^2a/cos^2a=2*sin^2b/cos^2b+2-1sin^2a/cos^2a+1=2*sin^2b/cos^2b+21/cos^2a=2/cos^2bcos^2b=2*cos^2a所以1-sin^2b = 2(1-sin^2)=2-2sin^2a整理得sin^b=2sin^2a-1
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