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分解因式法解一元二次方程
1.3(x-5)²=2(x-5)
2.(3-x)²+x²=9
3.49(x-3)²=16(x+6)²
4.3x(x+1)=2x+2
人气:104 ℃ 时间:2020-06-27 06:02:42
解答
1.3(x-5)²=2(x-5)3(x-5)^2-2(x-5)=0,(x-5)(3x-15-2)=0,(x-5)(3x-17)=0x-5=0,3x-17=0,x1=5,x2=17/32.(3-x)²+x²=99-6x+x^2+x^2=9,2x^2-6x=0,2x(x-3)=0x1=0,x2=33.49(x-3)²=16(x+6)²49(x-3)^2...
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