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分解因式:(x-2)^2-x+2 用简便方法计算:(2009^3-2×2009^2-2007)/(2009^3+2009^2-2010)
人气:276 ℃ 时间:2020-03-24 05:03:21
解答
(x-2)²-x+2
=(x-2)²-(x-2)
=(x-2)(x-2-1)
=(x-2)(x-3)
(2009³-2×2009²-2007)/(2009³+2009²-2010)
=[2009²(2009-2)-2007]/[2009²(2009+1)-2010]
=(2009²*2007-2007)/(2009²*2010-2010)
=2007(2009²-1)/[2010(2009²-1)]
=2007/2010
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