已知tanθ=2,求sin²θ+2sinθ*cosθ+1的值
人气:233 ℃ 时间:2020-04-08 13:11:55
解答
tanθ=2
sin²θ+2sinθ*cosθ+1
= (sin²θ+2sinθ*cosθ)/1 + 1
= (sin²θ+2sinθ*cosθ)/(sin²θ+cos²θ) + 1
前边分子分母分别除以cos²θ:
= (tan²θ+2tanθ)/(tan²θ+1) + 1
= (2²+2×2)/(2²+1) + 1
= 13/5
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