若sin2α=(根号2)/2,则sin^4α+cos^4α=?
人气:137 ℃ 时间:2019-12-22 18:52:47
解答
sin2α=(根号2)/2
sin^4α+cos^4α=(sin^2a+cos^2a)^2-2sin^2acos^2a=1-1/2 sin^2(2a)= 1 - 1/2*(√2/2)^2 = 3/4
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