①4x−1≤x−1化为4x−1−(x−1)≤0即：(x−3)(x+1)x−1≥0，由穿根法解得-1≤x＜1或x≥3不等式的解集为：{x|-1≤x＜1或x≥3}②4x+5x2−2x+8＞−1化为4x+5x2−2x+8+1＞0即：x2+2x+13x2−2x+8＞0即：(x+1)2+12(x−1)2...