已知当x→0时,x-sinx与ax^3是等价无穷小,求a
人气：257 ℃ 时间：2020-02-03 21:11:21
解答
lim(x→0) (x-sinx)/(ax^3)
=lim(x→0) (1-cosx)/(3ax^2)
=lim(x→0) (x^2/2)/(3ax^2)
=1/(6a)
=1
a=1/6
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