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代数计算2
已知x+y=7,xy=2,求:[1]2x^2+2y^2的值;[2][x-y]^2的值
人气:109 ℃ 时间:2020-04-12 14:33:14
解答
2x^2+2y^2
=2(x+y)^2 - 4xy
=14-8
=6
[x-y]^2
=(x+y)^2 - 4xy
=7-8
=-1
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