(3-2根号2)x²+2(根号2-1)x-1=0 解方程 跪求谢谢各位啦~~~急死人了
人气:158 ℃ 时间:2020-02-05 10:52:16
解答
(3-2√2)x^2 + 2(√2-1)*x -1 = 0(2-2√2+1)x^2 + 2(√2-1)*x -1 = 0(√2-1)^2*x^2 + 2(√2-1)*x -1 = 0((√2-1)*x)^2 + 2(√2-1)*x -1 = 0((√2-1)*x )^2+ 2(√2-1)*x +1= 2((√2-1)*x+1)^2 = 2(√2-1)*x+1 = √2 ...
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