1.通项:an=19+(n-1)*(-2)=21-2n
Sn=(a1+an)n/2=(19+21-2n)n/2=-n²+20n
2.bn-an=3^(n-1)
bn=21-2n+3^(n-1)
{bn-an}的前n项和为(1-3^n)/(1-3)=(3^n-1)/2
oh my gosh