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化简:x的平方-(y-1)的平方分之(x的平方-y的平方)乘(x的平方+2xy+y的平方)分之(x-y)的平方-1÷(x的平方+xy-2y的平方)分之(x的平方-xy)
人气:263 ℃ 时间:2019-12-12 21:26:18
解答
=(x+y)(x-y)/(x+y-1)(x-y+1)×(x-y+1)(x-y-1)/(x+y)²×(x+2y)(x-y)/x(x-y)
=(x-y-1)(x+2y)(x-y)/x(x+y-1)(x+y)
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