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解不等式(2+log3 x)log3 x>log3 (9x)
3都是底数
人气:456 ℃ 时间:2020-04-03 02:38:09
解答
(2+log3 x)log3 x>log3 (9x)
=>
(2+log3 x)log3 x>log3 (9)+log3 (x)
=>
(2+log3 x)log3 x>2+log3 (x)
设log3 (x)=t
=>
(2+t)t>2+t
=>
t^2+t-2>0 t>1 or t
log3 (x)>1 or log3 (x)
x>3 or 0
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