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已知:(x²-2x+3)/(x-2)³=A/(x-2)+B/(x-2)²+C/(x-2)³,求A,B,C的值
人气:139 ℃ 时间:2020-09-19 21:01:14
解答
A/(x-2)+B/(x-2)²+C/(x-2)³=(x²-2x+3)/(x-2)³(A(x-2)^2+B(x-2)+C)/(x-2)^3=(x²-2x+3)/(x-2)³(A(x^2-4x+4)+Bx-2B+C)/(x-2)^3=(x²-2x+3)/(x-2)³(Ax^2-4Ax+4A+Bx-2B+C)/...
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