> 数学 >
求数列之和
1/S1+1/S2+1/S3+```````+1/Sn
的值
我知道 Sn=n^2+2n
怎么求啊
人气:448 ℃ 时间:2020-04-03 13:26:53
解答
Sn=n^2+2n
1/Sn=1/(n^2+2n)=1/n(n+2)=1/2*[1/n-1/(n+2)]
1/S1+1/S2+1/S3+```````+1/Sn=1/2×[(1-1/3)+(1/2-1/4)+(1/3-1/5)+(1/4-1/6)+…+1/n-1/(n+2)]
=1/2×[1+1/2-1/(n+1)-1/(n+2)]
=3/4-(2n+3)/[2(n+1)(n+2)]
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