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初三一元二次方程--因式分解法
①3x^2=4x;②x(x-1)+3(x-1)=0;③3(x-5)^2=2(5-x);④3x^2-4x=2x;⑤x(x-6)=2(x-8)
人气:397 ℃ 时间:2020-06-06 02:44:20
解答
①3x^2=4x;3x²-4x=0x(3x-4)=0x1=0,x2=4/3②x(x-1)+3(x-1)=0;(x-1)(x+3)=0x1=1x2=-3③3(x-5)^2=2(5-x);3(x-5)²+2(x-5)=0(x-5)[3(x-5)+2]=0(x-5)(3x-13)=0x1=5x2=13/3④3x^2-4x=2x;3x²-4x-2x=...
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