f(x)=llog3xl在区间【a,b]上的值域为【0,1】所以x=1在【a,b]范围内,log3(3)=1,log3(1/3)=-1所以由log3x得图像可知在x∈[1/3,3]上log3x∈[-1,1]则f(x)=|log3x|∈[0,1]sorry~想少了~f(x)在[1,3],[1/3,1],或[1/3,3]上值...