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函数Y=log2(x^2+1)-log2x的值域
人气:245 ℃ 时间:2020-01-29 17:26:36
解答
Y = log 2 (x^2+1) - log 2 x
零和负数无对数:x>0
Y = log 2 (x^2+1) - log 2 x = log 2 {(x^2+1)/x} = log 2 {x+1/x}
x>0,x+1/x≥2,log 2 {x+1/x} ≥lgo 2 2 = 1
值域【1,+∞)
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