(1)
(2x-1)^2=x(3x+2)-7
4x^2-4x+1= 3x^2+2x-7
x^2-6x+8=0
(x-2)(x-4)=0
x=2 or 4
(2)
2(x-3)=3x(x-3)
2x-6=3x^2-9x
3x^2-11x+6 =0
(3x-2)(x-3)=0
x=2/3 or 3为什么x^2-6x+8的下一步是(x-2)(x-4)=0啊？？6x =(-2x)+(-4x)
8 = -2 x (-4)

x^2-6x+8

=(x-2)(x-4)