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lim(x趋于无穷大)(x^2+1/x+1 -ax-b)=0求a b
人气:259 ℃ 时间:2020-04-05 09:24:57
解答
∵ lim(x->∞)(x^2+1)/(x+1) -ax-b = 0∴ 0=lim(x->∞)[(x^2+1)/(x+1) -ax-b ] / x =lim(x->∞)[(x+1/x)/(x+1) -a-b/x=lim(x->∞)[(1+1/x^2)/(1+1/x) -a-b/x= 1 - a - 0 = 1-a∴ a = 1∴ lim(x->∞)(x^2+1...
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