> 数学 >
一道数学题:(2+1)*(2的4次方+1)*(2的8次方+1)*(2的16次方+1)*(2的32次方+1)+1
人气:381 ℃ 时间:2020-02-03 16:46:58
解答
题目好像抄漏了2^2+1项.
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)+1
=(2^8-1)(2^8+1)(2^16+1)(2^32+1)+1
=(2^16-1)(2^16+1)(2^32+1)+1
=(2^32-1)(2^32+1)+1
=2^64-1+1
=2^64
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版