设一元二次方程为x²-mx+n=0,得x1=-√2+√3；x2=-√2-√3m=x1+x2=-2√2,n=x1·x2=-1则一元二次方程为x²+2√2x-1=0 如果需要多组,只需整式同乘个不为0的系数即可.如x²+2√2x-1=0与2x²+4√2x-2=0,...