原式=a/(a+1)-(a+3)/(a-1)*(a-1)²/(a+1)(a+3)=a/(a+1)-(a-1)/(a+1)=(a-a+1)/(a+1)=1/(a+1)∵a是方程a^2+3a-1=0的一个根∴a=(-3±√13)/2∴a=(-3-√13)/2时,原式=1/[(-3-√13)/2+1]=1/[(-1-√13)/2]=2/(-1-√13)...