由根号的定义：x+y-8≥0 得x+y≥88-x-y≥0 得x+y≤8所以x + y = 8,左边=0右边根号（3x-y-a)≥0根号(x-2y+a+3)≥0两者相加=0所以3x-y-a = 0x-2y+a+3 =0-x+2y-3 = a = 3x-y3y-11 = a = 24-4yy = 5x = 3a = 4可以组成三...