f(x) = √3/2*sin(2x) - 1/2*cos(2x) - (cosx + sinx)(cosx - sinx) + 1= √3/2*sin(2x) - 1/2*cos(2x) - cos(2x) + 1= √3[1/2*sin(2x) - √3/2*cos(2x)] + 1= √3sin(2x - π/3) + 1所以最小正周期为πx∈[0,π/2]...