y=[sin(4x+3)]^3 y'=3[sin(4x+3)]^2*[sin(4x+3)]' =3[sin(4x+3)]^2*[cos(4x+3)]*(4x+3)' =12[sin(4x+3)]^2*[cos(4x+3)] y=sin(x^2)-sin(3x) y'=cos(x^2)*(x^2)'-cos(3x)*(3x)' =2xcos(x^2)-3cos(3x)