方程x^3-11x^2+9x-6=0有一个实根 (sqrt(5113)/6+1933/54)^(1/3)+94/(9*(sqrt(5113)/6+1933/54)^(1/3))+11/3,有两个虚根94*(sqrt(3)*i/2-1/2)/(9*(sqrt(5113)/6+1933/54)^(1/3))+(sqrt(5113)/6+1933/54)^(1/3)*(-sqrt...