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y=sin³(3x+π/4)的导数
人气:387 ℃ 时间:2019-09-17 15:49:20
解答
令3x+π/4=t
(sin^3t)'=((sin^2t)(sint))'
利用求导乘法法则
=(sin^2t)'sint+(sint)'sin^2t
对sin^2t再利用求导法则,得到
=(sint(sint)'+(sint)'sint)sint+costsin^2t
=(2sintcost)sint+costsin^2t
=2sin^2tcost+costsin^2t
=3costsin^2t
带入t=3x+π/4
=3cos(3x+π/4)sin^2(3x+π/4)
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