若x,y,z满足3x+7y+z=1,4x+10y+z=2006,求分式2005x+2005y+2005z/x+3y的值.
人气：190 ℃ 时间：2020-06-21 22:23:45
解答
3x+7y+z=1(1),4x+10y+z=2006 (2)(2)-(1),x+3y=2005 (3) 2005x+2005y+2005z/x+3y=x+y+z (3) 乘2：2x+6y=4010 (4)(1)-(4):x+y+z=-40092005x+2005y+2005z/x+3y=x+y+z =-4009
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