分解因式（x^2+2y+1)^2+10y+5+5x^2和（x^2+1)(x^2-xy+y^2)+2x^3y+2xy_数学解答

分解因式（x^2+2y+1)^2+10y+5+5x^2和（x^2+1)(x^2-xy+y^2)+2x^3y+2xy

人气：450 ℃　时间：2020-03-19 23:28:48

解答

(x^2+2y+1)^2+10y+5+5x^2
=(x^2+2y+1)^2+5(x^2+2y+1)
=(x^2+2y+1)(x^2+2y+1+5)
=(x^2+2y+1)(x^2+2y+6)
(x^2+1)(x^2-xy+y^2)+2x^3y+2xy
=(x^2+1)(x^2-xy+y^2)+2xy(x^2+1)
=(x^2+1)(x^2-xy+y^2+2xy)
=(x^2+1)(x^2+xy+y^2)