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设z=z(x,y)是由方程e^(-xy)+2z-e^z=2确定 求dz|(x=2,y=-1/2)
人气:292 ℃ 时间:2020-05-22 04:58:30
解答
对方程e^(-xy)+2z-e^z=2两边微分,有:e^(-xy)*d(-xy) + 2*dz - e^z*dz = 0-e^(-xy)*(x*dy + y*dx) + 2*dz - e^z*dz = 0移项,得:(e^z - 2)*dz = -y*e^(-xy)*dx - x*e^(-xy)*dy当x=2,y=-1/2时,代入e^(-xy)+2z-e^z=2,...
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