f(x)=cos2wx+√3sin2wx+m+1=2sin(2wx+π/6)+m+1由题意得：2w*π/6+π/6=π/2∴w=1f(0)=m+2=2∴m=0∴f(x)=2cosx^2+2√3sinxcosx=2sin(2x+π/6)+1f(x0)=11/5即：2sin(2x0+π/6)+1=11/5sin(2x0+π/6)=3/5x0∈(π/4,π/2...