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求极限limx~2 (4x^2+5)/(x-2)
人气:354 ℃ 时间:2020-03-12 08:42:38
解答
lim (4x²+5)/(x-2) = 21/0+ = +∞
x→2+
lim (4x²+5)/(x-2) = 21/0- = -∞
x→2-
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