> 数学 >
初一有理数计算题,
1/(2^2-1) +1/(3^2-1) +1/(4^2-1) +...+1/(19^2-1) +1/(20^2-1)
人气:188 ℃ 时间:2020-01-30 12:32:49
解答
1/(2^2-1) +1/(3^2-1) +1/(4^2-1) +...+1/(19^2-1) +1/(20^2-1)
= 1/(2^2-1^2) +1/(3^2-1^2) +1/(4^2-1^2) +...+1/(19^2-1^2) +1/(20^2-1^2)
=1/(2+1)(2-1) + 1/(3+1)(3-1) +……+1/(20+1)(20-1)
=1/2*3 + 1/3*4 +...+1/20*21
=(1/2 - 1/3) + (1/3-1/4) + (1/4-1/5)...+(1/19 - 1/20)
=1/2 - 1/20
=9/20
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版