(x^2-2x)(x^-1）^(-1）/[(x-1）—(2x-1·）(x+1)^（-2)],中x=二分之一怎么算呢_数学解答

(x^2-2x)(x^-1）^(-1）/[(x-1）—(2x-1·）(x+1)^（-2)],中x=二分之一怎么算呢

人气：498 ℃　时间：2020-08-29 11:58:58

解答

(x^2-2x)/（x^2-1)÷｛x-1-(2x-1)/(x+1)｝
=x(x-2)/(x+1)(x-1)÷[(x^2-1-2x+1)/(x+1)]
=x(x-2)/(x+1)(x-1)÷[x(x-2)/(x+1)]
=x(x-2)/(x+1)(x-1)*(x+1)/x(x-2)
=1/(x-1)
=-2.